5 solutions
-
1
#include<bits/stdc++.h> using namespace std; int a[1005], n, x, max1; int main() { scanf("%d", &n); for (int i = 0; i < n; i++) { scanf("%d", &x); a[x]++; } max1 = 1; for (int i = 0; i <= 1000; i++) { if (a[i] > a[max1]) { max1 = i; } else if (a[i] == a[max1] && i < max1) { max1 = i; } } printf("%d\n", max1); return 0; }
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0
#include <bits/stdc++.h> using namespace std;
int main() { int n, a[100005], x, maxi; scanf("%d", &n); for (int i = 0; i <= n; i++) { scanf("%d", &x); a[x] ++; }
maxi = 0; for (int j = 0; j <= 10005; j++) { if (a[j] > a[maxi]) { maxi = j; } else if (a[j] == a[maxi] && j < maxi) { maxi = j; } } printf("%d", maxi); return 0;
}
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-1
#include <bits/stdc++.h> using namespace std;
int main() { int n, a[100005], x, maxi; scanf("%d", &n); for (int i = 0; i <= n; i++) { scanf("%d", &x); a[x] ++; }
maxi = 0; for (int j = 0; j <= 10005; j++) { if (a[j] > a[maxi]) { maxi = j; } else if (a[j] == a[maxi] && j < maxi) { maxi = j; } } printf("%d", maxi); return 0;
}
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-1
#include <bits/stdc++.h> using namespace std;
int main() { int n, a[100005], x, maxi; cin >> n; for (int i = 1; i <= n; i++) { cin >> x; a[x]++; } maxi = 0; for (int j = 0; j <= 100005; j++) { if (a[j] > a[maxi]) { maxi = j; } else if (a[j] == a[maxi] && j < maxi) { maxi = j; } } printf("%d\n", maxi);
return 0;
}
- 1
Information
- ID
- 391
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- 7
- Tags
- # Submissions
- 62
- Accepted
- 14
- Uploaded By