5 solutions
-
-1
#include <bits/stdc++.h> using namespace std;
int main() { int n, a[100005], x, maxi; cin >> n; for (int i = 1; i <= n; i++) { cin >> x; a[x]++; } maxi = 0; for (int j = 0; j <= 100005; j++) { if (a[j] > a[maxi]) { maxi = j; } else if (a[j] == a[maxi] && j < maxi) { maxi = j; } } printf("%d\n", maxi);
return 0;
}
Information
- ID
- 391
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- 7
- Tags
- # Submissions
- 62
- Accepted
- 14
- Uploaded By